Read file and break the string line

Hi All,

I have a file with several lines and i would like to read it and break
the lines string in many parts and pass it as parameter and also skip
the first and the last line, as example.

File example.txt
1 #first line
XX12345678ABCDEYYYYY
XX99999999KKKKKMMMM
3 #last line

NUMBER=12345678
LETTERS=ABCDE
YEAR=YYYYY

and next

NUMBER=99999999
LETTERS=KKKKK
YEAR=MMMM


while read file; do
break the strings
NUMBER=12345678
LETTERS=ABCDE
YEAR=YYYYY
done < example.txt

Thanks in advance

Considering that the data has fixed length for the desired fields,
this script, though very crude, should work fine:-

#!/bin/bash

LINES=$(( `cat testdata | wc -l` - 1 ))
for i in `cat testdata | sed -n "2,$LINES p"`
do
echo -ne "$i\t"
NUMBER=`echo ${i:2:8}`
LETTERS=`echo ${i:10:5}`
YEAR=`echo ${i:15:4}`
echo -e "$NUMBER\t$LETTERS\t$YEAR"
done

7/29/2008 11:33 PM, Beto wrote:
Hi All,
>
I have a file with several lines and i would like to read it and break
the lines string in many parts and pass it as parameter and also skip
the first and the last line, as example.
>
File example.txt
1 #first line
XX12345678ABCDEYYYYY
XX99999999KKKKKMMMM
3 #last line
>
NUMBER=12345678
LETTERS=ABCDE
YEAR=YYYYY
>
and next
>
NUMBER=99999999
LETTERS=KKKKK
YEAR=MMMM
>
>
while read file; do
break the strings
NUMBER=12345678
LETTERS=ABCDE
YEAR=YYYYY
done < example.txt
>
Thanks in advance

awk 'NR>1{printf "%s",s;
s=sprintf("NUMBER=%s\nLETTERS=%s\nYEAR=%s\n",substr($0,3,8),substr($0,11,5),substr($0,16))}'
file

With GNU awk you could use fixed width fields in stead of ths substr()s.

Regards,

Ed.